# Answer to Question #11255 in Statistics and Probability for Ke_091

Question #11255

(a) A group of 5 boys and 4 girls are to be photographed. In how many ways can they be arranged such that:

(i) No two girls sit together?

(ii) No two boys sit together?

(i) No two girls sit together?

(ii) No two boys sit together?

Expert's answer

(i) we have at least this formation gbgbgbg

g- girl, b – boy.

2 boys that left can sit at random – there are 8*8=64 variants.

(ii) No two boys sit together

There is only one variant for this case

bgbgbgbgb

where b-boy, g-girl.

so answer equals& 1

g- girl, b – boy.

2 boys that left can sit at random – there are 8*8=64 variants.

(ii) No two boys sit together

There is only one variant for this case

bgbgbgbgb

where b-boy, g-girl.

so answer equals& 1

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