Answer to Question #11231 in Statistics and Probability for Bonnie Jones
At a particular restaurant, 63% of all customers order an appetizer and 40% of all customers order dessert. If 76% of all customers order an appetizer or dessert (or both), what is the probability a randomly selected customer orders both an appetizer and dessert?
In terms of probablity (A - appetizer oredered, B - desert ordered)
Using the formula:
P(AorB)=P(A)+P(B)-P(A&B) we get P(A&B)=63%+40%-76%=27% (probability we were looking for).
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