Answer to Question #107503 in Statistics and Probability for yoyo

Question #107503
Restaurant “King Steak” offers a set lunch of a 150 grams steak for $100. The steaks are cut by a machine
and the weight of a steak can be assumed to be normally distributed with mean 152 grams and standard
deviation 1.7 grams.
(a) What is the probability that a customer gets a steak that weighs less than 150 grams?
(b) There is a 4% chance that a customer gets a steak that weighs less than W grams. What is the value of
W?
(c) There is a table with 8 customers, everyone orders this set lunch. What is the probability that there are
exactly 2 customers whose steaks weigh less than 150 grams?
(d) Sometimes there are customers ordering two sets of lunch. Use T to denote the total weight of two
steaks. Find the mean, variance, and standard deviation of T.
1
Expert's answer
2020-04-02T12:54:25-0400

Let "X=" the weight of a steak:"X\\sim (N, \\sigma^2)"

Then "Z=\\dfrac{X-\\mu}{\\sigma}\\sim N(0,1)"

Given that "\\mu=152\\ g, \\sigma=1.7\\ g"

(a) What is the probability that a customer gets a steak that weighs less than 150 grams? 


"P(X<150)=P(Z<{150-152\\over 1.7})\\approx""\\approx P(Z<-1.17647)\\approx0.1197"

(b) There is a 4% chance that a customer gets a steak that weighs less than W grams. What is the value of W? 


"P(X<W)=P(Z<{W-152\\over 1.7})=0.04"

"{W-152\\over 1.7}\\approx-1.7507"

"W\\approx149\\ g"

(c) There is a table with 8 customers, everyone orders this set lunch. What is the probability that there are exactly 2 customers whose steaks weigh less than 150 grams? 

Let "Y=" the number of customers whose steaks weigh less than 150 grams: "Y\\sim Bin (n,p)"


"P(Y=y)=\\binom{n}{y}p^y(1-p)^{n-y}"

Given that "n=8, p=0.1197"


"P(Y=2)=\\binom{8}{2}(0.1197)^2(1-0.1197)^{8-2}\\approx0.1867"

(d) Sometimes there are customers ordering two sets of lunch. Use T to denote the total weight of two

steaks. Find the mean, variance, and standard deviation of T.


"T\\sim N(\\mu+\\mu,\\sigma^2+\\sigma^2)"

Then


"\\mu_T=150\\ g+150\\ g=300\\ g"

"Var(T)=\\sigma_T^2=1.7^2+1.7^2=5.78"

"\\sigma_T=\\sqrt{5.78}\\ g=1.7\\sqrt{2}\\ g\\approx2.4\\ g"


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS