Question #100323
A random sample is drawn from a population of known standard deviation 11.3. Construct a 90% confidence interval for the population mean based on the information given (not all of the information given need be used).
a. n = 36, x-=105.2, s = 11.2
b. n = 100, x-=105.2, s = 11.2
1
Expert's answer
2019-12-18T12:08:18-0500

a.

90%CI=(xˉ1.645sn,  xˉ+1.645sn)==(105.21.64511.236,  105.2+1.64511.236)==(102.13,  108.27).90\%CI=(\bar x-1.645\frac{s}{\sqrt{n}},\;\bar x+1.645\frac{s}{\sqrt{n}})=\\ =(105.2-1.645\frac{11.2}{\sqrt{36}},\;105.2+1.645\frac{11.2}{\sqrt{36}})=\\ =(102.13,\;108.27).


b.

90%CI=(xˉ1.645sn,  xˉ+1.645sn)==(105.21.64511.2100,  105.2+1.64511.2100)==(103.36,  107.04).90\%CI=(\bar x-1.645\frac{s}{\sqrt{n}},\;\bar x+1.645\frac{s}{\sqrt{n}})=\\ =(105.2-1.645\frac{11.2}{\sqrt{100}},\;105.2+1.645\frac{11.2}{\sqrt{100}})=\\ =(103.36,\;107.04).


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

Assignment Expert
24.02.21, 16:48

Dear Jorey, You are welcome. We are glad to be helpful. If you liked our service, please press a like-button beside the answer field. Thank you!

Jorey
21.02.21, 10:13

Thanks

LATEST TUTORIALS
APPROVED BY CLIENTS