Answer to Question #91366 in Real Analysis for Sajid

Question

Q. Choose the correct answer.
Q. The series ∑_(n=1)^∞▒〖(-1)〗^(n+1) n/(n^2+π) is
a. conditionally convergent for n>√π
b. absolutely convergent for n>Ï€^2
c. divergent for n>0
d. none of the above

Answer 1

1) The series of absolute values

$$\sum _{n=1}^{\infty } \frac{n}{n^2+\pi }$$

diverges because

$$\frac{n}{n^2+\pi } \ge \frac{n}{n^2+n^2 } = \frac{1}{2} \cdot \frac{1}{n}, n \ge 2,$$

and as you know the harmonic series diverges [https://en.wikipedia.org/wiki/Harmonic_series_(mathematics)].

2) The series

$$\sum _{n=1}^{\infty } \frac{(-1)^{n+1} n}{n^2+\pi }$$

converges by Leibniz's test [https://en.wikipedia.org/wiki/Alternating_series_test]. Absolute values decreases monotonically because the derivative is negative

$$\left(\frac{n}{n^2+\pi }\right)' = \frac{\pi -n^2}{\left(n^2+\pi \right)^2} < 0, n \ge 2.$$

3) $n$ is a local variable inside the series. Thus, the correct answer is automatically "d. none of the above". But we found that the original series converges conditionally (regardless of n).