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Answer to Question #8381 in Real Analysis for Jim

Question #8381
Prove: If f and g are differentiable and a is in the real numbers, then (fg)'(a) = f(a)g'(a) + f'(a)g(a) and (f/g)'(a) = (g(a)f'(a)-f(a)g'(a))/g(a)^2.
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