# Answer to Question #8251 in Real Analysis for mike

Question #8251

suppose f and g are differentiable at a. Then, prove f/g is differentiable at a, and

(f/g)'(a)= f'(a)g(a)-f(a)g'(a)/ (g(a))^2.

(f/g)'(a)= f'(a)g(a)-f(a)g'(a)/ (g(a))^2.

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