# Answer on Real Analysis Question for Shiro

Question #4227

Show that a set of real numbers E is bounded if and only if there is a positive number r so that absolute value x<r for all x in e.

Expert's answer

A set S of real numbers is called bounded from above if there is a real number k such that k ≥ s for all s in S. The number k is called an upper

bound of S.A set of real numbers is bounded from below if there is a real number

m such that s>=m fo all s in S. m is lower bound .

A set S is bounded if it has both upper and lower bounds.

1. =>

set S is bounded=> it has lower and upper bounds, respectively m and k. m=>k

if m,k>0 then we take r=m and |x|<r for all x in S (cause in this case x>0 and |x|=x)

if m>0, k<0 then we take r=max{m, |k|}

if m,k<0 r=|k|

2.<=

assume |x|<r for all x in S

Hence -r<x<r for all x

so x>-r bounded from below

x<r bounded from above

bound of S.A set of real numbers is bounded from below if there is a real number

m such that s>=m fo all s in S. m is lower bound .

A set S is bounded if it has both upper and lower bounds.

1. =>

set S is bounded=> it has lower and upper bounds, respectively m and k. m=>k

if m,k>0 then we take r=m and |x|<r for all x in S (cause in this case x>0 and |x|=x)

if m>0, k<0 then we take r=max{m, |k|}

if m,k<0 r=|k|

2.<=

assume |x|<r for all x in S

Hence -r<x<r for all x

so x>-r bounded from below

x<r bounded from above

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