Answer to Question #3985 in Real Analysis for Junel
Then there exists such x0 - element of D, that f(x0) <= supremum f(D) and
at the same time f(x0) >infinum g(D). As we know, f(x) <= g(y) for all x, y from D.
f(x0) <= g(y) for all y from D. But this statement proves that f(x0) is infinum g(D).
We came to the contradiction because f(x0) > infinum g(D).
So, out assumption was wrong and supremum f(D) <= infinum g(D).
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