64 727
Assignments Done
99,4%
Successfully Done
In September 2018

Answer to Question #16571 in Real Analysis for steve peters

Question #16571
assume that lim[1+2(-1)^n]Xn = 0. Prove that lim Xn exists and find it.
Expert's answer
if n=2k then lim[1+2(-1)^n]Xn=lim[1+2(-1)^(2k)]X2k=lim3*X_(2k)
if n=2k+1 then
lim[1+2(-1)^(2k+1)]Xn=lim(-1)*X_(2k+1)
then for subsequences
0=lim3*X_(2k)=3lim X_(2k) and 0=lim(-1)*X_(2k+1)=-lim X_(2k+1)

so we
have lim X_(2k)=lim X_(2k+1)=0 so limit exist and equal 0

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be first!

Leave a comment

Ask Your question

Submit
Privacy policy Terms and Conditions