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Answer to Question #14301 in Real Analysis for hoor

Question #14301
if a,b,c are real numbers show that min{a,b,c}=min{min{a,b},c}
Expert's answer
Without loss of generality we can assume that a<=b<=c then min{a,b,c}=a
and min{min{a,b},c}=min{a,c}=a.

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