Answer to Question #22613 in Math for Fahad

Question

You wish to scan an 8 by 10 colour photograph using a scanner which can scan images at a resolution of 3200 dots per inch. The image will be scanned using 8 bit colour, i.e. 1 byte for each of the 3 colours R,G,B
a) How many bytes are required to store the photograph?
b) If your USB flash memory key has 16 GB of storage space. Using the definitions of a MB and a GB above , how many such images could be stored on your memory key?
c) If the photograph was in 8 bit grey scale rather than colour, how many such images could be stored on your memory key?

Answer 1

a) How many bytes are required to store the photograph?
B = A * dpi * 3, where A stands for area, dpi stands forresolution.
B = 8 * 10 * 3200 * 3 = 240 * 3200 = 768000 bytes
b) If your USBflash memory key has 16 GB of storagespace. Using
the definitions ofa MB and a GB above, how many such images could be stored on your memory key?
S = 16 GB = 17179869184 B, so there could be stored n = S/ B = 17179869184/ 768000 = 22369 such images.
c) If the photograph was in 8 bit grey scale rather than color,
how many such images could be stored on your memory key?
There could be stored three times more images, or 67108.