Answer to Question #15008 in Other Math for sora
Newton’s method. Set up the Newton’s iteration for solving x^3 − b = 0,and write down the formula for xn+1 in terms of xn.
x(n+1) = x(n) - f(x(n))/f'(x(n)).
So, in the case of f(x) = x³-b we have the following formula:
x(n+1) = x(n) - ((x(n))³-b)/(3(x(n))²).
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