Answer to Question #147364 in Math for Sean

Question

Suppose a person standing at the top of a building 112 ft high throws a ball vertically upward
with an initial velocity of 96 ft/sec.
(a) Find the velocity of the ball at time

Answer 1

We have given the height of building:

h_building=112ft and the initial velocity:

V_initial=96ft/sec.

We need to find velocity at time but time did not given therefore we take time at t.

V_t=V_initial+g*t, --> g=9.81 m/sec²=32.18ft/sec².

V_t=96ft/sec+t*32.18ft/sec² --> this is velocity of ball that it reaches V_t at time t.