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Answer to Question #10710 in Math for manthankhorwal
Question #10710
Simplify usinf identites:
186*186*186+14*14*14/186*186-186*14+14*14
186*186*186+14*14*14/186*186-186*14+14*14
Expert's answer
(186*186*186+14*14*14)/(186*186-186*14+14*14)
Let's recall that a3+b3=(a+b)(a2-ab+b2) . In the numerator we have sum of two cubes, in the denominator the second braces from the right part of mentioned formula. Therefore
(186*186*186+14*14*14)/(186*186-186*14+14*14)=(186+14)(186*186-186*14+14*14)/(186*186-186*14+14*14)= =186+14=200
Let's recall that a3+b3=(a+b)(a2-ab+b2) . In the numerator we have sum of two cubes, in the denominator the second braces from the right part of mentioned formula. Therefore
(186*186*186+14*14*14)/(186*186-186*14+14*14)=(186+14)(186*186-186*14+14*14)/(186*186-186*14+14*14)= =186+14=200
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#340153 on Dec 2023
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