# Answer to Question #9529 in Geometry for Candice

Question #9529

Sub 24
Ques. 16
Find the length of a side of each of two squares given that the sum of their perimeters is 44 ft and the sum of their areas is 73 ft^2.

Expert's answer

x^2+y^2 = 73

4x+4y = 44, x +y = 11, x = 11- y

(11 - y)^2 +y^2 = 73,

y^2 -11y +24 = 0, y1 = 3, y2 = 8

x1 = 8, x2 = 3.

So the sides are 3 ft and

8 ft

4x+4y = 44, x +y = 11, x = 11- y

(11 - y)^2 +y^2 = 73,

y^2 -11y +24 = 0, y1 = 3, y2 = 8

x1 = 8, x2 = 3.

So the sides are 3 ft and

8 ft

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