Question #6279

If the legs of a triangle are 7 cm and the base is 5 cm, what is the area?

Expert's answer

Consider triangle ABC:

We know that AB=BC=7 cm, AC=5cm.

Let's draw height BD. As long as AC=BC , the height BD is also a median: AD=DC=AC/2=2.5

Consider triangle BDC, its right angled. Let's find BD using Pethagorean theorem:

BD^2+DC^2=BC^2

Hence BD=sqrt(BC^2-DC^2)=sqrt(7^2-2.5^2)= approx. 6.54

Now we can find area:

S=1/2*AC*BD=1/2*5*6.54=16,35 cm^{2}

We know that AB=BC=7 cm, AC=5cm.

Let's draw height BD. As long as AC=BC , the height BD is also a median: AD=DC=AC/2=2.5

Consider triangle BDC, its right angled. Let's find BD using Pethagorean theorem:

BD^2+DC^2=BC^2

Hence BD=sqrt(BC^2-DC^2)=sqrt(7^2-2.5^2)= approx. 6.54

Now we can find area:

S=1/2*AC*BD=1/2*5*6.54=16,35 cm

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