# Answer to Question #6028 in Geometry for Samantha

Question #6028

A triangle has sides a=5 and b=4 and angle C=60degrees. Find the length of side c.

Expert's answer

we can use cosine theorem

c^2=a^2+b^2-2*a*b*cos(60)=25+16-2*5*4*1/2=21

so

c=sqrt(21)

c^2=a^2+b^2-2*a*b*cos(60)=25+16-2*5*4*1/2=21

so

c=sqrt(21)

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