Question #5673

the perimeter of a right triangle is 24cm. one leg is 2cm longer than the other leg and 2cm shorter than the hypotenuse. find the area of the right triangle

Expert's answer

Let's construct the system of equations (a and b are legs and c is the hypotenuse):

a+b+c = 24

a+2 = b

a-2 = c

Solving it:

a+(a+2)+(a-2) = 24

3a = 24

a = 8

b = 10

Here we got both legs of the triangle. So, the area of the triangle is

S = a*b/2 = 8*10/2 = 40 cm^2.

a+b+c = 24

a+2 = b

a-2 = c

Solving it:

a+(a+2)+(a-2) = 24

3a = 24

a = 8

b = 10

Here we got both legs of the triangle. So, the area of the triangle is

S = a*b/2 = 8*10/2 = 40 cm^2.

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