Question #377

If line segment JK is parallel to the line segment LM, ∠JKM = 2x²+15 and ∠LMK=29x-45, find ∠JKM. There is a parallelogram KLMJ with diagonal KM.

Expert's answer

2x²+15 = 29х -45 => x1 = 5/2; x2 = 12 => ∠JKM = 2*144+15 = 303 - it is impossible, because angle is sharp, or ∠JKM = 2*25/4 + 15 = 55/2 - this is an answer.

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