# Answer to Question #28418 in Geometry for Jack

Question #28418

A can of paint covers 2.5 m2 of a wall. How many cans are needed to paint a square wall with a side length of 6 meters?

Expert's answer

First ofall we need to find the area of the wall. Area of square can be found by the

next formula: S=a*a, where 'a' is aside length of square. So, in our case we have a=6 m, therefore we obtain: S = 6*6=36(m^2)

One can ofpaint covers 2.5m^2 of a wall, sowe can calculate a number of the cans needed as: 36/2.5 = 14.4 (cans).

But wecan’t buy only 0.4 of the one can! So, the number of cans is the closest

greater integer to 14.4 and that is 15.

next formula: S=a*a, where 'a' is aside length of square. So, in our case we have a=6 m, therefore we obtain: S = 6*6=36(m^2)

One can ofpaint covers 2.5m^2 of a wall, sowe can calculate a number of the cans needed as: 36/2.5 = 14.4 (cans).

But wecan’t buy only 0.4 of the one can! So, the number of cans is the closest

greater integer to 14.4 and that is 15.

**Answer:15.**Need a fast expert's response?

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