Answer to Question #244626 in Geometry for keif

Question

if the endpoints of a line segment are (14, -8) and (4,12) what would the midpoint be? use the midpoint formula: (Xm, Ym)= (x1+x2, y1+y2)

2 2

Answer 1

Given the endpoints of a line segment are (14,-8) and (4,12)

This means $x_1=14,y_1=-8,x_2=4,y_2=12$

Mid point formula:(cm,my)=$(\frac{x_1+x_2}{2}),(\frac{y_1+y_2}{2})= (\frac{14+4}{2}),(\frac{-8+12}{2})\\ =(\frac{16}{2}),(\frac{4}{2})\\=(8,2)$

The midpoint of the line segment will be (8,2)