Question #23915

if a ramp is 20 feet long and 28 inches high, what is the angle of the ramp?

Expert's answer

As one foot is equal to 12 inches,

20[f] = 12[i]*20 = 240[i].

The tangent of the angle of the ramp is

tg(α) = 28[i]/240[i] = 7/60.

Therefore, the angle of the ramp is

α = arctg(7/60) ≈ 6.65°.

20[f] = 12[i]*20 = 240[i].

The tangent of the angle of the ramp is

tg(α) = 28[i]/240[i] = 7/60.

Therefore, the angle of the ramp is

α = arctg(7/60) ≈ 6.65°.

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