# Answer to Question #22385 in Geometry for zainab irfan

Question #22385

the length of a rectangle is 7cm longer than width f the perimeter is 74cm find the length and the area of the rectangle

Expert's answer

We have that f = length - 7

and that perimeter

P = 74 =2*(f+length)

= 2*(length - 7+ length) =

= 2*(2*length -7)

2*(2*length -7) = 74

2*length - 7 =37

2*length =37+7=44

length = 44/2 =22

Therefore

width = f =length - 7 = 22-7 = 15

and thearea of the rectangle is

A = width *length = 15*22 = 330

Answer:

length = 22 cm

area = 330 cm^2

and that perimeter

P = 74 =2*(f+length)

= 2*(length - 7+ length) =

= 2*(2*length -7)

2*(2*length -7) = 74

2*length - 7 =37

2*length =37+7=44

length = 44/2 =22

Therefore

width = f =length - 7 = 22-7 = 15

and thearea of the rectangle is

A = width *length = 15*22 = 330

Answer:

length = 22 cm

area = 330 cm^2

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