# Answer to Question #21670 in Geometry for zack

Question #21670

Find an equation of the circle whose diameter has endpoints (-4,6) and (6,-4)

Expert's answer

equation of the circle:

(x-x0)^2+(y-yo)^2=r^2

where x0, y0 - center, r- radius

r=d/2

d^2=(-4-6)^2+(6+4)^2=200

r^2=d^2/4=50

x0=(-4+6)/2=1

y0=(6-4)/2=1

Answer:

(x-1)^2+(y-1)^2=50

(x-x0)^2+(y-yo)^2=r^2

where x0, y0 - center, r- radius

r=d/2

d^2=(-4-6)^2+(6+4)^2=200

r^2=d^2/4=50

x0=(-4+6)/2=1

y0=(6-4)/2=1

Answer:

(x-1)^2+(y-1)^2=50

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