Answer to Question #2132 in Geometry for jade
AB: A(-8, -2) B (-3,3)& m& = 1
BC: B (-3,3) C (3,-3)& m = -1
CD: C (3,-3) D(-2,-8) m = 1
DA: D(-2,-8) A(-8, -2)& m =-1
Thus AB is parallel to CD, BC is parallel to DA, as their slopes are equal to each other respectively, AB is perpendicular to BC, and BC is perpendicular to CD, as m(AB) = -m(BC) nad m(BC) = -m (CD). This shows that ABDC is a rectangle.
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