Answer on Geometry Question for jade
AB: A(-8, -2) B (-3,3)& m& = 1
BC: B (-3,3) C (3,-3)& m = -1
CD: C (3,-3) D(-2,-8) m = 1
DA: D(-2,-8) A(-8, -2)& m =-1
Thus AB is parallel to CD, BC is parallel to DA, as their slopes are equal to each other respectively, AB is perpendicular to BC, and BC is perpendicular to CD, as m(AB) = -m(BC) nad m(BC) = -m (CD). This shows that ABDC is a rectangle.
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