# Answer to Question #19774 in Geometry for Kyland

Question #19774

each side of a square checkerboardmeasurees 40 cm. what is is the length of the diagonal of the board

Expert's answer

We can use Pythagoras Theorum. PythagorasTheorum is basically this: C squared = A squared + B squared. A is the length

of the chekerboard, B is the width of the checkerboard and C is the length of

the diagonal. So the checkerboard is square then both A and B are 40cm, we

would need to square each of them (so A^2 and B^2 instead of being 40cm becomes

1600cm^2 ) then we add them together (1600 plus 1600 = 3200) and after that we

find the square root of the answer ( the square root of 3200 = 56.569... so C is

equal to 56.569...( in other words the diagonal of the chekerboard is 56.6cm [

rounded of to the nearest tenth cm]

of the chekerboard, B is the width of the checkerboard and C is the length of

the diagonal. So the checkerboard is square then both A and B are 40cm, we

would need to square each of them (so A^2 and B^2 instead of being 40cm becomes

1600cm^2 ) then we add them together (1600 plus 1600 = 3200) and after that we

find the square root of the answer ( the square root of 3200 = 56.569... so C is

equal to 56.569...( in other words the diagonal of the chekerboard is 56.6cm [

rounded of to the nearest tenth cm]

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