# Answer to Question #17140 in Geometry for Leslie

Question #17140

slope midpoint distance for (-5,6) AND (1, -8)

Expert's answer

slope=(y2-y1)/(x2-x1)=(6-(-8))/(-5-1)=-14/6=-7/3

midpoint

x=(x1+x2)/2=(-5+1)/2=-2

y=(y1+y2)/2=(6+(-8))/2=-1

distance=sqrt(

(x1-x2)^2+(y1-y2)^2)=sqrt(36+14^2)=sqrt(232)=2sqrt(58)

midpoint

x=(x1+x2)/2=(-5+1)/2=-2

y=(y1+y2)/2=(6+(-8))/2=-1

distance=sqrt(

(x1-x2)^2+(y1-y2)^2)=sqrt(36+14^2)=sqrt(232)=2sqrt(58)

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