Answer to Question #16646 in Geometry for lola
S2 = ¾ * S1 => for sides of the square the following holds: a2 = a1*sqrt(3)/2.
Fold the square in half, you will get the segment of the length a1/2. Straightenit out.
Now choose the vertex of the square, and draw a circle of radius a1 / 2with the center in it.
Choose the vertex neighbor to the first vertex and draw a tangent from thepoint of this vertex to the circle from the previous step.
The distance between the length of this tangent will be a1* sqrt(3)/2,because the square triangle was formed with cathetus of a length a1 / 2 and
hypotenuse of length a1.
So, we get the segment of length a1* sqrt(3)/2. Now choose some vertex, measure this lengthalong two sizes of the square, and fold the square in the points of ends of
these segments along sizes of the square.
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