# Answer to Question #15258 in Geometry for Chris

Question #15258

find the distance and midpoint of the coordinates A:(2,8) & (-4,0)

Expert's answer

The distance between (2,8) and (-4,0) is sqrt(

(-4-2)^2+(0-8)^2)=10

The midpoint has coordinates ((-4+2)/2,(0+8)/2)=(-1,4)

(-4-2)^2+(0-8)^2)=10

The midpoint has coordinates ((-4+2)/2,(0+8)/2)=(-1,4)

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