# Answer to Question #14088 in Geometry for manthan khorwal

Question #14088

AOB is a triangle with coordinates of A and O as (4,0) and (0,0),AB=5.Find the coordinates of B.

Expert's answer

In common, (x(B) - 4)^2 + (y(B) - 0)^2 = AB^2.

BO^2 + AO^2 = AB^2

AO =

sqrt( (0 - 0)^2 + (4 - 0)^2 ) = 4

AB = 5

BO = sqrt( AB^2 - AO^2 ) =

3

x(B) = x(0) = 0

y(B) = sqrt( BO^2 - (x(B))^2 ) = 3

So, getting

B(0,3).

BO^2 + AO^2 = AB^2

AO =

sqrt( (0 - 0)^2 + (4 - 0)^2 ) = 4

AB = 5

BO = sqrt( AB^2 - AO^2 ) =

3

x(B) = x(0) = 0

y(B) = sqrt( BO^2 - (x(B))^2 ) = 3

So, getting

B(0,3).

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