Show that the square of an even number is an even number using a direct proof.
Let n∈Zn\in\mathbb{Z}n∈Z - even number, so n=2zn=2zn=2z, where z∈Zz\in\mathbb{Z}z∈Z.
n2=(2k)2=22k2=2⋅(2k2)n^2=(2k)^2=2^2k^2=2\cdot(2k^2)n2=(2k)2=22k2=2⋅(2k2) - is an even number because it is divisible by 2.
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