Answer on Discrete Mathematics Question for Sujata Roy
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It is straightforward to compute the connected components of a graph in linear time (in terms of the numbers of the vertices and edges of the graph) using either breadth-first search or depth-first search. In either case, a search that begins at some particular vertex v will find the entire connected component containing v (and no more) before returning. To find all the connected components of a graph, loop through its vertices, starting a new breadth first or depth first search whenever the loop reaches a vertex that has not already been included in a previously found connected component.
There are also efficient algorithms to dynamically track the connected components of a graph as vertices and edges are added, as a straightforward application of disjoint-set data structures. These algorithms require amortized O(α(n)) time per operation, where adding vertices and edges and determining the connected component in which a vertex falls are both operations, and α(n) is a very slow-growing inverse of the very quickly growing Ackermann function. A related problem is tracking connected components as all edges are deleted from a graph, one by one; an algorithm exists to solve this with constant time per query, and O(|V||E|) time to maintain the data structure; this is an amortized cost of O(|V|) per edge deletion. For forests, the cost can be reduced to O(q + |V|log|V|), or O(log|V|) amortized cost per edge deletion.
Then sir please tell me about the algorithm.