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Answer to Question #79776 in Differential Equations for promise
Question #79776
Solve the equation
x dy/dx−ay=x+1
, where a is a constant
a. y=x/1−a − 1/a+cx
b. y=x/1−a + 1/a+cx
c. y=x/1+a − 1/a+cx
d. y=−x/1−a − 1/a+cx
x dy/dx−ay=x+1
, where a is a constant
a. y=x/1−a − 1/a+cx
b. y=x/1−a + 1/a+cx
c. y=x/1+a − 1/a+cx
d. y=−x/1−a − 1/a+cx
Expert's answer
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#339914 on Dec 2023
#339914 on Dec 2023
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