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Answer to Question #79196 in Differential Equations for prromise ayansola
Question #79196
Solve the differential equation y′=x(1+y2)
y=tan(x/2+c)
y=−tan(x/2+c)
y=−tan(x^2/2+c)
y=tan(x^2/2+c)
y=tan(x/2+c)
y=−tan(x/2+c)
y=−tan(x^2/2+c)
y=tan(x^2/2+c)
Expert's answer
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#340153 on Dec 2023
#340153 on Dec 2023
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