Answer to Question #25830 in Differential Equations for jacob Milne
u(x,y) = x^2+y^2
At first we need to calculate u_x and u_y and then substitute obtained expressions into the initial equation:
u_x = d/dx[ x^2+y^2] = 2x
u_y = d/dy[ x^2+y^2] = 2y
y*u_x = y*2x = 2xy
x*u_y = x*2y = 2xy
yu_x - xu_y = 2xy - 2xy = 0
Therefore the given function is a solution of our pde.
Answer:& the function given by u(x,y) = x^2+y^2 is a solution of the pde yu_x - xu_y = 0
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