Answer to Question #177684 in Differential Equations for John

Question

Differentiate with respect to x

f(x) = 6x

y = 12e^5x

y = ln3x

Answer 1

f(x) = 6x

$\frac d{dx}(6x) = 6 \frac d{dx}(x) = 6 \cdot 1 = 6$

y = 12e^5x

$\frac d{dx}(12e^{5x}) = 12\frac d{dx}(e^{5x}) = 12e^{5x}\frac d{dx}(5x) = 12e^{5x} \cdot 5 = 60e^{5x}$

y = ln3x

$\frac d{dx}(\ln3x) = \frac1{3x}\frac d{dx}(3x) = \frac1{3x}\cdot 3 = \frac1x$