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Answer to Question #7290 in Complex Analysis for yvonne
Question #7290
(5+i3) + (2+i8) (convert to polar form)
Expert's answer
(5+i3) + (2+i8) = (5+2) + (i3+i8) = 7 + i11 = ...
x = 7>0, y = 11>0;
r = sqrt(x²+y²) = sqrt(7²+11²) = sqrt(170)
α = arctan(y/x) = arctan(11/8)
... = r(cosα + isinα) = r(cosα + isinα) = sqrt(170)*(cos(arctan(11/8)) + i*sin(arctan(11/8))).
x = 7>0, y = 11>0;
r = sqrt(x²+y²) = sqrt(7²+11²) = sqrt(170)
α = arctan(y/x) = arctan(11/8)
... = r(cosα + isinα) = r(cosα + isinα) = sqrt(170)*(cos(arctan(11/8)) + i*sin(arctan(11/8))).
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