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Answer to Question #4979 in Complex Analysis for Gb
Question #4979
Find all values of z, e^(2iz)=-1
Expert's answer
-1=e^i(pi+2*pi*k) where k - integer
so we have e^(2iz)=-1=e^i(pi+2*pi*k)
Hence 2iz=i(pi+2*pi*k)
=> z=(pi+2*pi*k)/2& where k -integer
pi=3.14.15926...
so we have e^(2iz)=-1=e^i(pi+2*pi*k)
Hence 2iz=i(pi+2*pi*k)
=> z=(pi+2*pi*k)/2& where k -integer
pi=3.14.15926...
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