69 577
Assignments Done
Successfully Done
In February 2019

Answer to Question #4979 in Complex Analysis for Gb

Question #4979
Find all values of z, e^(2iz)=-1
Expert's answer
-1=e^i(pi+2*pi*k) where k - integer
so we have e^(2iz)=-1=e^i(pi+2*pi*k)
Hence 2iz=i(pi+2*pi*k)
=> z=(pi+2*pi*k)/2& where k -integer

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!


No comments. Be first!

Leave a comment

Ask Your question

Privacy policy Terms and Conditions