# Answer on Complex Analysis Question for Gb

Question #4979

Find all values of z, e^(2iz)=-1

Expert's answer

-1=e^i(pi+2*pi*k) where k - integer

so we have e^(2iz)=-1=e^i(pi+2*pi*k)

Hence 2iz=i(pi+2*pi*k)

=> z=(pi+2*pi*k)/2& where k -integer

pi=3.14.15926...

so we have e^(2iz)=-1=e^i(pi+2*pi*k)

Hence 2iz=i(pi+2*pi*k)

=> z=(pi+2*pi*k)/2& where k -integer

pi=3.14.15926...

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