"a=2i+2j-k,\\;\\;b=6i-3j+2k."
"cos\\theta=\\frac{ab}{|a||b|}=\\frac{2*6+2*(-3)+(-1)*2}{\\sqrt{2^2+2^2+1^2}\\sqrt{6^2+3^2+2^2}}=\\frac{4}{21}".
"\\theta=arccos(\\frac{4}{21})\\approx79^0 ."
Answer d.
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