# Answer to Question #6705 in Combinatorics | Number Theory for Jeremy

Question #6705

If o(E) = 5:7, find o(E').

o(E') =

o(E') =

Expert's answer

E’ is an opposite set(event/probability) to the set(event/probability) E

So the sum of o(E)+ o(E') always equals 1

o(E)+ o(E') =1

5/7 + o(E') =1

o(E') =2/7=2:7

So the sum of o(E)+ o(E') always equals 1

o(E)+ o(E') =1

5/7 + o(E') =1

o(E') =2/7=2:7

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