Answer to Question #4398 in Combinatorics | Number Theory for Bliss
ii) no couples are included insuch a group
at first time we can pick nvariants
second- n-2(cannot pick 1 couple one member of whitchis picked)
So ans n(n-2)...(n-2k)/(2k)!
iii) at least one couple isincluded in such a group
C2k2n-all variants to pick up 2k from 2n
n(n-2)..(n-2k)/(2k)! it does not fitus.
So ans:C2k2n - n(n-2)..(n-2k)/(2k)!
iv) exactly two couples are included in such a group.
C2n-so many ways areto pick 2 couples
C2k-42n-4-we pick from 2n-4people 2k-4 places in our group
so ans. C2n*C2k-42n-4
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