Answer to Question #19111 in Combinatorics | Number Theory for Jazmyne
Repetition: If you have 4 green circles, 3 red circles, and 2 black circles, how many distinct arrangements could you make?
We have 4+3+2=9 circles, then we can make 9!=362882 arrangements. Since 4 green, 3 red and 2 black circles are the same, then we need to divide the number of arrangements by (4!*3!*2!). Finally the number of distinct arrangements is: 9!/(4!*3!*2!)=1260
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