# Answer to Question #15026 in Combinatorics | Number Theory for abdel007

Question #15026

There are 20 people on the board of directors of a publicly listed company. Each pair of people are either friends or enemies with each other. Every person has exactly 6 enemies on the board. If every group of 3 directors form a committee, what is the total number of committees that are formed by all friends or all enemies?

Expert's answer

At first, let's see the possibilities of one person. A person has 6 enemies and 14 friends.

He can form a committee of other two members by either selecting 2 from 6 enemies or 2 from 14 friends. That can be done in

N = C(6,2) * C(14,2).

Now, all the 20 persons have the possibility of

M = 20 * N = 20 * C(6,2) * C(14,2) = 27300.

He can form a committee of other two members by either selecting 2 from 6 enemies or 2 from 14 friends. That can be done in

N = C(6,2) * C(14,2).

Now, all the 20 persons have the possibility of

M = 20 * N = 20 * C(6,2) * C(14,2) = 27300.

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