Answer to Question #117718 in Combinatorics | Number Theory for vanesa martinez

Question

the electric depot received 108 mp3 players, 12 of which are defective . in how many different ways can 6 players be selected if a) nome are defective b) half are defective c) all are defective

Answer 1

Total players =108

defective players =12

non- defective players=108-12=96

We have to select 6 players

a) no player is defective

no. of ways to do so = $^{96}C_6$

b) half are defective

which means out of 6 , 3 are defective and 3 are non

no of ways to do so =$^{96}C_3.^{12}C_3$

c) all are defective

no. of ways to do so = $^{12}C_6$