Answer to Question #98135 in Calculus for Jerico

Question

Evaluate Integrals. Show complete solution.

3. Integral of 1/ 2u^2 minus 3u^3/2 minus 2u^5/ 3 du
4. Integral of 2t^6 + 5t^2 +7 / t^2 dt

Answer 1

$3) \int$ (1/(2u²) -3u³/2-2u⁵/3)du= (-1/2u)-3u⁴/8-2u⁶/6+C =(-1/2u)-3u⁴/8-u⁶/3+C.

4) $\int$ (2t⁶+5t²+7/t²)dt= 2t⁷/7+5t³/3-7/t +C.