Let's find a slant asymptote of this curve
Let's rewrite the equation
x3+y3−3axy=0
The slant asymptote is y=mx+c
Substuting this to the equation will give us
x3+(mx+c)3−3ax(mx+c)=(1+m2)x3+(3m2c+3am)x2+(3mc2−3ac)x+c3=0
Therefore
1+m3=0;m=−1
3m2c−3am=0;mc−a=0;c=−a
Hence y=−x−a is a slant asymptote of this curve
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