Note that for P(21, 28) we get x=21 and y=28.
Consider O(0; 0), then "OP=\\sqrt{21^2+28^2}=" "\\sqrt{441+784}=\\sqrt{1225}=35".
sin θ="\\frac{opposite side}{hypotenuse}=\\frac{y}{OP}=\\frac{28}{35}=\\frac{4}{5}."
Answer: sin θ"=\\frac{4}{5}" .
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