Question #84926

Find the volume of the solid of revolution formed when the arc of the parabola
y^2= 4ax between x = 0 and x = a is resolved about the x − axis

Expert's answer

Answer on Question #84926 – Math – Calculus

Question

Find the volume of the solid of revolution formed when the arc of the parabola y2=4axy^2 = 4ax between x=0x = 0 and x=ax = a is resolved about the xx-axis.

Solution

y=f(x)y = f(x)y2=f2(x)=4axy^2 = f^2(x) = 4axV=π0af2(x)dx=π0a4adx=2πax20a=2πa(a20)=2πa3V = \pi \int_{0}^{a} f^2(x) \, dx = \pi \int_{0}^{a} 4a \, dx = 2\pi a x^2 \Big|_{0}^{a} = 2\pi a (a^2 - 0) = 2\pi a^3


Answer: 2πa32\pi a^3.

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