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Answer to Question #80391 in Calculus for Anand
Question #80391
Say true or false
The tangent to the curve, x^3 + 6y^2 +5x =0 at (-1,1) is perpendicular to the y- axis
The tangent to the curve, x^3 + 6y^2 +5x =0 at (-1,1) is perpendicular to the y- axis
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